Young’s double slit introduction | Light waves | Physics | Khan Academy
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Young’s double slit introduction | Light waves | Physics | Khan Academy


– [Voiceover] Young’s
Double Slit experiment looked a little something like this. You’ve got a barrier with two holes in it, but these holes are so
small and so close together we characterize them as slits, and double because there’s two of them. Young was the English physicist who first did an experiment of this kind. What we do nowadays is we take a laser, and we shine this laser
at the double slit. The laser has to be wide
enough that it hits both holes. You might think, oh my
god, you need a big laser. No, you make these holes
very close together. That’s why you make them
really close together, or at least one reason. The other reason is the distance between these holes has to be comparable. It doesn’t have to be
the same size or smaller, but it has to be around. It can’t be a trillion times bigger than the wavelength of this laser light you’re sending in here. It’s got to be around the same size, or what we’re going to talk
about here you won’t see. You won’t see the interesting pattern that’s going to emerge. You might wonder I’ve drawn here. What is this? This isn’t a wave. This is a wave, right here. I thought these were waves. What are we doing now? Why have we got this
different representation? The reason is, when I draw this, this pretty much just lets me
show a wave in one dimension. But that’s not good enough. This process is going to be
fundamentally two-dimensional. This wave’s going to spread
out in two dimensions, so I can’t draw it like this, I have to draw it like this. This whole line here,
what does this represent? This represents a peak. Everywhere along here
is a peak of the wave, so you’ve got this wave
filling up this entire region. These lines represent
lines where every point along there is a peak of the wave. What’s in the middle? Yup. In the middle would be
the trough of the wave, or the valley. That’s what I’m going to use. I’m going to use this
representation for the wave. This will let me show this wave spreading out in two dimensions
better than this one could. I couldn’t draw it very
well with this one. So, what happens? This wave comes in here, this
laser light comes in here. That part hits that barrier,
it doesn’t get through. This part hits that barrier,
it doesn’t get through. This part hits the barrier,
it doesn’t get through. The only portion that’s
going to get through is basically this portion
here and this portion here. These are going to be the
ones that make it through. What happens? What do you see on the wall over here? If this was a screen
that you could project the light on, what would you see? Naively, what I would have
thought would have been, okay, shoot, light comes
through here, bright spot. Light comes through here, bright spot. You just get two bright spots, right? Well, no, that’s not what you get. That’s why this experiment is interesting, because you don’t just
get two bright spots. You get a pattern over here, because waves don’t just travel
straight through this hole. When a wave encounters a hole or a corner, it spreads out. That spreading out we call diffraction. You’re going to get a wave
spreading out from down here. This is not going to
go in a straight line. It spreads out in two dimensions. That’s why I had to use this
wave drawing representation. It’s going to spread out
from the top one, too. Uh-oh, look what’s going to happen. You’re going to have
two waves overlapping. These two waves are going
to start overlapping, and where they overlap constructively, you’d get a bright spot, and where they overlap destructively, you’d get a dark spot. Where it’s sort of half
constructive, half destructive, you might get a mediumly bright spot. How do we figure out what’s going to be? Well, I can’t draw this precise enough to show you that, so let me get rid of all of this mess real
quick, get rid of that. Out of the bottom hole,
what would you get? You’d get this, a nice spherical
pattern coming out of here. It might not exactly be the
same intensity throughout here, but I can’t draw it with
the exact right intensity. Up here, this intensity of this portion would be smaller than this portion here, the degree to which it’s spreading, but this will help me visualize it. You’ve got this wave spreading out, out of the bottom hole. You also have a wave
spreading out of the top hole. Now these are going to overlap. Let’s draw them both, boom. Waves overlapping. In the same region you’re going to have constructive and destructive interference. If you look, remember,
these lines represent peaks, so every time a peak lines
up right over a peak, or in the middle, a valley over a valley, every time the wave is exactly in phase, when it gets to the same point, these are all constructive points, so right in the middle
you’d get a big bright spot. That’s kind of weird. Right in between these holes
there’d be a big bright spot. Where else? Well, look at this. This is constructive,
constructive, all constructive. They form a line, they get these lines of constructive interference. Same with this line,
constructive, constructive, all the way over to here. So on the wall, you’d see
multiple bright spots. Down here, these are all constructive because peaks are lining up perfectly. I’d get another one here. You’d keep getting these
bright spots on the wall. They wouldn’t last forever. At some point, it’d start to die off. It’d be hard to see, but you’d be getting these bright spots continuing on. At some point, they’re so
dim you can’t see them. In the middle, well, wherever … Let’s see, what’s a good point to look at? Wherever a peak lines up with a valley, so this wave’s a peak right here, but for the other wave, lookit, we’re in between the two green lines, so in that point you’ll have destructive, because the peak is
matching up with the valley. This would be destructive and
this would be destructive, so in between here you
get a destructive point. The same is true, in between each of these perfectly constructive points, you’d get a perfectly destructive point, and in between those it’d
be kind of half constructive half destructive, would
merge into each other, and what you’d get, sometimes physicists draw a little graph to represent this, you get a bright spot in the middle. This is sort of representing a graph of the intensity zero, and
then another bright spot, and it goes down to zero
again, another bright spot. They get weaker and weaker as you go out. At some point, it’s hard to see. Same on this side. Zero, bright spot, zero, bright spot. This is the classic double slit pattern you’ll see on the wall, and it’s caused by wave
interference in two dimensions. What’s the rule for wave
interference in two dimensions? The same rule as the wave
interference for one dimension. It was this, remember. For one dimension, delta X,
the path length difference had to be zero, lambda,
two lambda, three lambda, so on, would give us
constructive interference. Now, if you’re paying close attention, you might say, “Hold on,
there was a condition.” Remember, this was only
true if there was no funny switcheroo business
with the back of the speaker. We had to make sure that these two sources were in phase to start off with. Is that true of these light waves? It is. In fact, that’s why we do
it double slit like this. That’s why we take one
wave, we let one wave come through here. That way, we break it
up into two pieces. Why? Because we know if a peak
was going into the top hole, well, the same wave was
going into the bottom hole, that’s also a peak. This is a tricky way, a quick, easy way to make sure your two sources coming out of these two holes are exactly in phase. You don’t have to worry about any phase difference caused by the source. You just have to worry
about a phase difference caused by the fact that
these waves are going to travel different distances
to different points. What do I mean by this? What does path length
difference mean here? Well, if I look at it from this top line, or this top hole, this is
basically like our speaker, one source here and one source here, but it’s light instead of sound waves, from here to the center bright spot, the wave from the top hole had to travel a certain distance, and
from the bottom hole to that spot, the wave had
to travel a certain distance. Basically, this we can call
X one, this length X two. The path length difference
would be X one minus X two. The difference in these,
and you can just made it the absolute value if you want, but the size of the difference between these two path lengths,
what is that going to be? For right in the center, that one’s just delta X equals zero, because the waves are
traveling the same distance to get to that point. That makes sense. That’s a constructive point because zero gives you a constructive point when the path length difference is zero. How about the next point? The wave from the bottom
has to travel this far. The wave from the top hole
has to travel this far. This time, they’re not
traveling the same distance. The wave from the bottom
hole is traveling farther. How much farther? It’s got to be the next one, it’s got to be lambda. So this wave’s going to be traveling– the bottom wave would travel
one wavelength further to get to this point than
the wave from the top hole because that’s the next possibility for constructive interference. Note, it’s not from here to
there that’s one wavelength. This is a common misconception. This distance on the wall
between constructive points is not one wavelength. The difference in path
length that one wave travels to get there
compared to the other wave is one wavelength. I bet you can guess the next one. The next one, delta X, would
just be two wavelength, and you can keep going. How about the destructive points? Shoot, you know how to do that. These are going to be
the half wavelengths, lambda over two. This one’s going to be
three lambda over two, and so on. Down here, what would you get? Well, if you got rid of
the absolute value sign and you wanted to, you
could start talking about this delta X would be negative one lambda. This one would be negative
two lambda, and so on. You could have negative
values if you wanted to note the fact that there might be lower or higher, depending on where you were in this interference pattern.

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100 thoughts on “Young’s double slit introduction | Light waves | Physics | Khan Academy

  1. Iam a bit confused about this experiment..but with this vid my confusions just got rid off….thank u very much 😃 for uploading this video…

  2. isnt that a double slit exp. in which interference takes place and gives alternate dark and bright bands of equal intensity.

  3. for my problem, all i am given is two different wavelengths and the difference in length to object for the two different wavelengths to line up. I am supposed to solve for the original distance that the lower wavelength laser was further from object

  4. if two interfering wavelets have the same amplitude A, then a bright fringe will be of intensity :
    INTENSITY max = K(a+a)^2 = Constant.
    Thus all the bright fringes have the same intensity.

  5. you are wrong and the intensity does not go on decreasing but alternative bright and dark lines are observed where every bright line are of equal intensity.

  6. i never had an intuitive understanding until i watched this video. The impact you are having on the world is deeply profound.

  7. But in the original experiment he set up an observer to look at the light, then it behaved as a particle, please explain this

  8. Intensity pattern drawn here is of Diffraction phenomenon but Young's experiment shows Interference….so Intensity should be max at bright fringes and zero at dark ones..

  9. I spent 1 hour in lecture and 1 hour in lab and was so confused as to understanding the constructive/destructive interference, the first minute at 40 seconds answered just that. BIG THANKS.

  10. "How 'bout the destructive points?…shoooot, you know how to do that. These are gonna be the half wavelengths." Love it. Thanks again Khan.

  11. Wow!!!! You are a hero! I just woke up and stressed about how these wave interfere, but you made it like a piece of cake 😊 thank you very much. I still have a question about diffraction. Say the slit gap is exactly same as one wavelength of that particular length. After it is diffracted it spreads out, so does that mean that same wave’s wavelength increases as it moves forward ? And the same amount of waves go through that slit each time? As I have seen water pressure increases through holes. Does pressure make the amount of water flow increase too? Or again it is just as it spreads out it’s wavelength increases? Pleaseeeeeeeee help

  12. Thank god Sal didn't taught this topic or else I don't think I could have understood so well…………..Thank you so much Khan Academy for uploading this video.

  13. Thanks for explaining this! I am curious…what about the observation part of it? I watched a video talking about when the light was measured/observed during this experiment, it behaves differently than when it's not. Do you know anything about that?

  14. this is a question "young double _slit experiment is performed with 589 nm light and a distance of 2 m between the slits and the screen . the tenth interference minimum is observed 7.26 mm from the central maximum. determine the spacing of the slits .

  15. first time in my life, i have realized what the circular form of wave representation means, all after passing everything, huh

  16. In interference the intensity of every fringe is equal. And you drew it incorrectly in the screen.

  17. 7:09 but the waves seem to be interfering before they touch the display surface and not directly on the point , They are interfering at the dots mentioned and travelling to the display surface. How can we assume and calculate distances traveled so to find intensities?

  18. You can experiment this at home easily. Here's prototype: https://www.youtube.com/watch?v=dI2vdHytozY

  19. in one of the websites it says that constructive interference occurs when the phase difference between the two waves is an even multiple of pi which would be pi, 3pi, 5pi,etc. but in this video he said 0,pi,2pi,3pi,etc. i am confused.

  20. Dude, i'm from Brazil and I'm really thankful for this video. I wasn't understanding a bit of what my college's teacher was saying, you'll save my exercises. Keep doing a great job!

  21. I still feel a bit confused about the intensity pattern… For the single slit, the intensity of subsidiary maxima is smaller than the intensity of the central maxima. However, for double slit, isn't the intensity should be the same for all maxima? Maybe I'm wrong.

  22. Sir , The explanation enhanced my understanding. If I didnt watch this video , I would have lived under a rock with thousands of confusions So sir, I would like to thank you and would encourage you to keep up the good work for us , students.

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